B13: Automatic Street Light Control Circuit

How NPN transistor works? Tutorials of forward & reverse biasing of an NPN transistor

This entry is part 5 of 6 in the series Bipolar Transistors

Let us know first what is a transistor? If you are already familiar with it, skip to next topic, below.

Transistor is a semiconductor device having three layers, three terminals and two junctions. Since we have only two types of semiconductors i.e. the p-type and n-type, there are two types of transistors: they are NPN transistor and PNP transistor.

It is named as transistor which is an acronym of two terms: “transfer-of-resistor.” It means that the internal resistance of transistor transfers from one value to another values depending on the biasing voltage applied to the transistor. Thus it is called TRANSfer resISTOR: i.e. TRANSISTOR.

Bipolar Transistor

A bipolar transistor is a semiconductor device in which electric current flows due to electrons and holes BOTH, simultaneously. Thus both types of charges take part in the conduction of current through it. Hence it is called bipolar transistor. There are two types of bipolar transistors, NPN and PNP transistor.

NPN Transistor

It uses three semiconductor layers: two n-type layers and one p-type layer. The p-layer is sandwiched between two n-layers, as shown below.

Important Points about NPN Transistor

  1. The area of collector layer is largest. So it can dissipate heat quickly.
  2. Area of base layer is smallest and it is very thin layer.
  3. Area of emitter layer is medium.
  4. Collector layer is moderately doped. So it has medium number of charges (electrons).
  5. Base layer is lightly doped. So it has a very few number of charges (holes).
  6. Emitter layer is heavily doped. So it has largest number of charges (electrons).
  7. There are two junctions in this transistor – junction J-1 and junction J-2.
  8. The junction between collector layer and base layer is called as collector-base junction
    or c-b junction.
  9. The junction between base layer and emitter layer is called as base-emitter junction
    or b-e junction.
  10. The two junctions have the same potential barrier voltage of 0.6V to 0.7V, just like in a diode.

Concept of Transistor Biasing

When external voltage is applied to the junction of transistor in such a direction that it cancels out the potential barrier, so that electric current flows through it, is called as transistor biasing.

Now to obtain easy current flow through the transistor it must be biased by connecting external batteries. So there must be two batteries to apply proper bias across the two junctions of the transistor.

For example, the NPN transistor can be biased using three different methods –

FF biasing: In this method both the junctions are forward biased. For this, two external batteries are connected across two junctions such that collector is negative w.r.t. base and base is positive w.r.t. emitter. This method is not useful as the transistor is in “saturation” and the current cannot be controlled easily.

RR biasing: In this method both the junctions are reverse biased. For this, two external batteries are connected across two junctions such that collector is negative w.r.t. base& base is negative w.r.t. emitter. This method is also not useful as the transistor is in “cut-off” state since current is zero.

FR biasing: This is the most common and popular method used in transistor biasing. In this method, the base-emitter junction is forward biased and collector-base junction is reverse biased.

For this, two external batteries are connected across two junctions such that collector is positive w.r.t. base and base is positive w.r.t. emitter. So by adjusting base voltage we can control total current in the transistor easily.

Forward Biasing of NPN Transistor

The NPN transistor can be used in two different modes: forward biased mode and the reverse biased mode. In forward biased mode, the electric current can easily flow through it. So it acts like a CLOSED SWITCH. However, in reverse biased mode, the current through it is practically zero and thus, it acts like an OPEN SWITCH.

image 16 Vidyasagar Academy Akola

To forward bias an NPN transistor it is connected as shown in the above circuit. Read following points to understand the process easily –

  1. The collector is connected to high positive voltage with respect to base i.e. Vcb is very high. So c-b junction is reverse biased. Vcb >> Vbe.
  2. The base is connected to low positive voltage with respect to emitter i.e. Vbe is low.
  3. When we increase Vbe 0.7V (potential barrier voltage) the transistor is forward biased.
  4. Now large number of electrons in emitter layer is repelled by negative terminal of Vbe and they flow towards b-e junction.
  5. They cross the junction and enter into small base layer. Here some electrons combine with holes. Also some of them are attracted by positive terminal of Vbe and remaining maximum number of electrons flow into collector layer, crossing the second junction i.e. c-b junction.
  6. The resident electrons of collector are repelled by these (guest) electrons and thus, all the electrons are attracted by positive terminal of Vcb.
  7. Thus, all these electrons complete their journey back into emitter layer and thus, produce conventional currents in the transistor as shown in the above circuit.
  8. Thus, as per Kirchhoff Current Law, we can write: Ic + Ib = Ie
  9. Now when Vbe is still increased, more electrons are repelled by negative terminal of Vbe. So base-emitter junction is more and more forward biased. Thus the base current (Ib) increases.
  10. Hence, we can say that collector current (Ic) is the function of base current (Ib).
  11. So collector current is directly proportional to the base current i.e. Ic ∝ Ib.
  12. Maximum number of electrons from emitter layer flow into collector layer. So collector current is ALMOST EQUAL to emitter current, i.e. Ic ≈ Ie.

Reverse Biasing of NPN Transistor

In this method both the junctions are reverse biased as the batteries are connected in opposite direction as shown in the adjacent diagram. The Vcb battery reverse biases CB junction. Similarly, the Veb battery reverse biases BE junction. So charges cannot flow and current in the transistor is practically zero.

image 17 Vidyasagar Academy Akola


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Yash Vidyasagar
Yash Vidyasagar

Professor in Department of CS, Fergusson College, Pune. Researcher in Embedded Systems, Expert in Online/Offline Education, Creator of lots of projects for community solutions... ➤➤

25 Comments

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    • May I please know what sort of more description you need further?
      Please reply, so that I can make necessary updates and enrich my website.
      Thanks for visiting the site…

  2. Points missing..How are the electrons penetrating through the reverse biased b-c junction(insulator)?
    ,what is the reason for small and lighted doped base(reduce time and recombination) and others too,
    technically speaking transistor is dc to ac power converter.

    • Your queries can be explained in short as follows…

      • Here we have to consider the minority charge carriers. When a large reverse biased PD is applied across the BC junction, these minority charges acquire strong repulsive force and they CAN NOW penetrate through the junction.
      • The reason that the base is small in size and lightly doped are as follows…
      • When transistor is forward biased, a large number of negative charges flow towards BE junction.
      • When they enter in base region, due to small space, they acquire further mutual repulsive force among them.
      • Due to this they have sufficient KE to cross the reverse biased CB junction.
      • Also in base layer we don’t want to “waste” electrons, within holes.
      • So the doping concentration of base is less.

      Also, I thank you for putting this query, as me too, was thinking of writing down a short note on these points in particular.
      Thanks also for visiting the site.
      Please don’t hesitate to point out the “points” missing…by sparing out of your valuable time….

  3. really confusing for someone who has no background

    from fwd bias-> f) Now large number of electrons in emitter layer is repelled by negative terminal of Vbe and they flow towards b-e junction.

    why are the electrons in emitter layer is repelled when it’s connected to negative junction of the battery which is also full of electrons??

    • The reason that the Vcb >> Vbe, is as follows….

      • The CB junction is reverse biased.
      • So it has large physical gap than BE junction, as this junction is forward biased.
      • When electrons come from emitter layer into base layer, they are crowded in small area of base.
      • So they acquire sufficient repulsive force among them to go into collector layer.
      • But this force is still slightly less than the required force to overcome CB junction barrier.
      • So a strong attractive force from collector side is required to pull these electrons towards collector layer and then towards +ve terminal of battery.
      • Hence the Vcb >> Vbe.
  4. In the base junction negative terminal of Vcb and positive terminal of Vbe
    is connected. Vcb grater then Vbe . So electrons should flow towards base .
    So current should flow out of the base. ( opposite to diagram )
    Then why current is flowing towards base ?

    Please explain ………

    I don’t understand this basic concept …..

    • My dear friend,

      • The BE junction is forward biased. So the physical barrier within it is more easy to surmount for electrons coming from emitter layer.
      • Once then enter base layer, they have strong mutual repulsion among them.
      • So some of them have the tendancy to get attracted towards the +ve terminal of Vbe.
      • Hence base current (conventional current) flows INTO base, rather than coming out…!
      • But don’t consider the -ve terminal of Vcb battery, since it is NOT CONNECTED to BE junction, it is connected to CB junction.
      • So you are not allowed to consider the ELECTRICAL CONNECTIVITY of Vcb with this process.
      • Please also read the explanation given on your next comment.
        I like the way, you are asking the queries. It increases the wisdom of understanding this process in deep.

  5. sir,

    I have doubt when npn transistor is on or off i.e is it right if the voltage at the base is more than the emiter volage applied the transistor is on.
    I would also like to know when does the transistor act as switch as well as CMOS working.

    • It is always the case, that when voltage across base-emitter junction of NPN transistor is greater than or equal to 0.7V, then it is forward biased.

      When this voltage is quite large, say around 3V or more (upto certain limit), then total the number of free electrons in emitter layer start participating in conduction of electric current through the transistor.
      This condition is called as saturation of transistor and in this condition we can use it just like a switch which is ON.
      And when the base voltage is quickly reduced to zero, this process of conducting current suddenly stops and we can use the transistor just like a switch which is OFF…!

      What type of CMOS info you need?

        • Inverter is defined as the circuit that converts DC voltage source into AC voltage at required frequency.
          Now CMOS-FET inverter is a device which is actually a FET (Field Effect Transistor) in CMOS technology.
          CMOS-FET inverter is a simply a push-pull type FET circuit as shown below, which amplifies both halves of the AC cycle and give you reliable output of AC source.

    • Since the current through the transistor is controllable, it means that the internal resistance of the transistor is changing. The fact that when its base-emitter resistance changes it reflects the change in its collector-emitter resistance.
      Hence it is termed as transfer of resistance-transistor.

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